tiny.preserves.preserve

1/// Returns `v` unchanged. Code that passes a value through the pattern conversions calls it for the2/// same signature as the others. The call ignores `alloc` and allocates nothing. The call never3/// fails, and the error union in its type exists for the root's signature alone.4pub fn preserve(alloc: std.mem.Allocator, v: AnyValue) !AnyValue {5    return any_conversions.preserve(alloc, v);6}

1pub const preserve = any.preserve;